Przekątna podstawy
[tex]d = a \sqrt{2} = 8 \sqrt{2} cm[/tex]
Przekątna graniastosłupa
[tex](8 \sqrt{2} {)}^{2} + {6}^{2} = {x}^{2} \\ 64 \times 2 + 36 = {x}^{2} \\ 128 + 36 = {x}^{2} \\ 164 = {x}^{2} \\ x = \sqrt{164} \\ x = \sqrt{4 \times 41} \\ \boxed{x = 2 \sqrt{41} cm}[/tex]
