[tex]Dane:\\R = 10 \ \Omega\\U = 10 \ V\\t = 60 \ s\\q = 20 \ C\\Szukane:\\W = ?\\P = ?[/tex]
Rozwiązanie
Praca prądu elektrycznego:
[tex]W = U\cdot I\cdot t\\\\ale \ \ I = \frac{q}{t}, \ zatem\\\\W = U\cdot\frac{q}{t}\cdot t\\\\W = U\cdot q\\\\W = 10 \ V\cdot20 \ C\\\\\boxed{W = 200 \ J}[/tex]
Moc:
[tex]P = \frac{W}{t}\\\\P = \frac{200 \ J}{60 \ s}\\\\\boxed{P\approx3,3 \ W}[/tex]
