[tex] \sqrt{1 \frac{9}{16} } \times {4}^{2} - ( \frac{1}{4} {)}^{3} = \sqrt{ \frac{25}{16} } \times 16 - \frac{1}{64} = \frac{5}{4} \times 16 - \frac{1}{64} = \frac{80}{4} - \frac{1}{64} = 20 - \frac{1}{64} = 19 \frac{63}{64} [/tex]
Odp.B
Odpowiedź:
[tex]\sqrt{1\frac{9}{16}}*4^2-(\frac{1}{4})^3=\sqrt{\frac{25}{16}} *4^2-(\frac{1}{4})^3=\frac{5}{4} *4^2-(\frac{1}{4})^3=20-\frac{1}{64}=19 \frac{63}{64}[/tex]
Odp: B
Szczegółowe wyjaśnienie:
