Zakładam, że chodzi o 12 i 13, bo 11 nie ma na zdjęciu.
12.
[tex]4\frac{1}{5} -1\frac{3}{5} = 2\frac{3}{5}[/tex]
odp. W garnku zostało [tex]2\frac{3}{5}[/tex] litra wody.
13.
[tex]\frac{2}{3} + \frac{1}{3} = \frac{3}{3} = 1\\\\\frac{4}{3} + \frac{1}{3} = \frac{5}{3}\\\\5 - \frac{1}{3} = 4\frac{2}{3}\\\\2\frac{1}{3} + \frac{1}{3} =2 \frac{2}{3}\\\\\frac{7}{3} - \frac{1}{3} = \frac{6}{3}\\\\3\frac{1}{3} - \frac{1}{3} = 3\\\\6\frac{2}{3} + \frac{1}{3} = 7\\\\5\frac{1}{3} - \frac{1}{3} = 5\\\\[/tex] [tex]\frac{1}{7} + \frac{4}{7} = \frac{5}{7}\\\\4 - \frac{4}{7} = 3\frac{3}{7}\\\\1\frac{2}{7} + \frac{4}{7} = 1\frac{6}{7}\\\\2\frac{3}{7} - \frac{4}{7} = 1\frac{6}{7}\\\\3\frac{2}{7} - \frac{4}{7} = 2\frac{5}{7}\\\\3\frac{3}{7} + \frac{4}{7} = 4\\\\\frac{5}{7} - \frac{4}{7} = \frac{1}{7}\\\\2\frac{1}{7} - \frac{4}{7} = 1\frac{4}{7}\\[/tex]
