[tex]Dane:\\m = 200 \ kg=2\cdot10^{2} \ kg\\E_{k} = 0,16 \ MJ = 0,16\cdot1000000 \ J = 160 \ 000 \ J=16\cdot10^{4} \ J\\Szukane:\\v = ?\\\\Rozwiazanie\\\\E_{k} = \frac{mv^{2}}{2} \ \ \ |\cdot2\\\\mv^{2} = 2E_{k} \ \ \ /:m\\\\v^{2} = \frac{2E_{k}}{m}\\\\v = \sqrt{\frac{2E_{k}}{m}}}[/tex]
[tex]v = \sqrt{\frac{2\cdot16\cdot10^{4} \ J}{2\cdot10^{2} \ kg}}} = \sqrt{16\cdot10^{2}\frac{kg\cdot\frac{m^{2}}{s^{2}}}{kg}}} = 4\cdot10\frac{m}{s}\\\\\boxed{v = 40\frac{m}{s}}[/tex]
Odp. To ciało porusza się z prędkością v = 40 m/s.
