[tex]Przedstawiona\ figura\ to\ prostokat\ o\ bokach\ a=8\frac{2}{5}\ cm i \ b=6\ cm .\\\\Pole\ prostokata\ wyraza\ sie\ wzorem:\\\\P=a*b\\\\P=8\frac{2}{5} *6=\frac{42}{5}*6=\frac{252}{5}=50\frac{2}{5}\ cm^2\\\\Obwod\ prostokata:\\\\Owb=2a+2b\\\\Owb=2*8\frac{2}{5}+2*6=2*\frac{42}{5}+12=\frac{84}{5}+12=16\frac{4}{5}+12=28\frac{4}{5}\ cm\\\\odp.\ \ Pole\ tego\ peostokata\ wynosi\ 50\frac{2}{5}\ cm^2\ \ a\ obwod\ 28\frac{4}{5}\ cm .[/tex]
