[tex]a)\\\\4x^2-4x+1 \leq 0\\a > 0 \text{ramiona skierowane w gore}\\\Delta=(-4)^2-4*4*1=16-16=0\\x_0=\frac{4}{8}=\frac12\\f(x) \leq 0 \text{ dla } x=\frac12[/tex]
[tex]b)\\\\-x^2+6x < -16 /+16\\-x^2+6x+16 < 0\\\\\Delta=6^2-4*(-1)*16=36+64=100\\\sqrt{\Delta}=10\\\\x_1=\frac{-6-10}{-2}=\frac{-16}{-2}=8\\x_2=\frac{-6+10}{-2}=\frac4{-2}=-2\\\\a < 0 - \text{ramiona skierowane w dol}\\f(x) < 0 \text{ dla } x \in (-\infty; -2)U(8; \infty)[/tex]
