Odpowiedź:
[tex](3x-2)^2 < 9\\\\(3x)^2-2\cdot3x\cdot2+2^2 < 9\\\\9x^2-12x+4 < 9\\\\9x^2-12x+4-9 < 0\\\\9x^2-12x-5 < 0\\\\a=9\ \ ,\ \ b=-12\ \ ,\ \ c=-5\\\\\Delta=b^2-4ac\\\\\Delta=(-12)^2-4\cdot9\cdot(-5)=144+180=324\\\\\sqrt{\Delta}=\sqrt{324}=18\\\\x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-18}{2\cdot9}=\frac{12-18}{18}=\frac{-6}{18}=-\frac{1}{3}\\\\x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+18}{2\cdot9}=\frac{12+18}{18}=\frac{30}{18}=\frac{5}{3}=1\frac{2}{3}[/tex]
