Odpowiedź:
[tex]c(x.y) \\ c \: srodek \\ x = \frac{6 + 2}{2} = 4 \\ y = \frac{ - 4 + - 8}{2} = - 6 \\ \\ \\ a \: srodek \\ \frac{2 + x}{2} = 6 > > > x = 10 \\ \frac{ - 8 + y}{2} = - 4 > > > y = 0 \\ \\ b \: srodek \\ \frac{6 + x}{2} = 2 > > > x = - 2 \\ \frac{ - 4 + y}{2} = - 8 > > > y = - 12[/tex]
