Odpowiedź:
[tex]2log_{5}4-3log_{5}\frac{1}{2}=log_{5}4^2-log_{5}(\frac{1}{2})^3=log_{5}\left(\dfrac{4^2}{(\frac{1}{2})^3}\right)=log_{5}\left(\dfrac{16}{\frac{1}{8}}\right)=\\\\=log_{5}(16:\frac{1}{8})=log_{5}(16\cdot8)=log_{5}128=log_{5}2^7=7log_{5}2\\\\\\Odp.B[/tex]
[tex]log_{a}x-log_{a}y=log_{a}(\frac{x}{y})[/tex]
