Odpowiedź:
[tex]A.\ \ 3^3\cdot9^2=3^3\cdot(3^2)^2=3^3\cdot3^4=3^{3+4}=3^7\\\\\\B.\ \ (5^3)^5\cdot25^2=5^{15}\cdot(5^2)^2=5^{15}\cdot5^4=5^{15+4}=5^{19}\\\\\\D.\ \ (-3)^4+(-2)^5=81+(-32)=81-32=49=7^2\\\\\\E.\ \ \dfrac{x^8\cdot x^7}{x^5\cdot(x^2)^3}=\dfrac{x^{8+7}}{x^5\cdot x^6}=\dfrac{x^1^5}{x^{5+6}}=\dfrac{x^1^5}{x^1^1}=x^{15-11}=x^4[/tex]
