Odpowiedź :
[tex]\frac{x-2}{x+2} =\frac{1}{3}\\3(x-2) = x+2\\3x-6=x+2\\2x=2+6\\2x=8 /:2\\x=4[/tex]
a = x
b = x+4
a = 4
b = 4+4=8
Obw = 2a + 2b = 2*4 + 2*8 = 8 + 16 = 24
[tex]\frac{x-2}{x+2} =\frac{1}{3}\\3(x-2) = x+2\\3x-6=x+2\\2x=2+6\\2x=8 /:2\\x=4[/tex]
a = x
b = x+4
a = 4
b = 4+4=8
Obw = 2a + 2b = 2*4 + 2*8 = 8 + 16 = 24