[tex]Zad.1\\\\a)\\11^2=121\\17^2=289\\15^2=225\\6^3=36*6=216\\3^3=9*3=27\\\\b)\\\sqrt{676}=26\\\sqrt{288}=\sqrt{144*2}=12\sqrt2\\\sqrt{\frac{36}{144}}=\frac6{12}=\frac12[/tex]
[tex]Zad. 2\\\\a)\\12^3=144*12=1728\\15^2=225\\16^2=256\\\\b)\\\sqrt[3]{64}=\sqrt[3]{4^3}=4\\\sqrt[3]{512}=\sqrt{64*8}=\sqrt{4^3*2^3}=8\\\sqrt{256}=16[/tex]
Odpowiedź:
1. a)
11² = 121
17² = 289
15² = 225
6³ = 216
3³ = 27
1. b)
[tex]\sqrt{626} = \sqrt{626}[/tex]
[tex]\sqrt{288} = \sqrt{2*144} = 12\sqrt{2}[/tex]
[tex]\sqrt{\frac{36}{144}} = \frac{6}{12} = \frac{1}{2}[/tex]
2.
12² = 144
15² = 225
16² = 256
[tex]\sqrt[3]{64} = 4[/tex]
[tex]\sqrt[3]{512} = 8[/tex]
[tex]\sqrt{256} = 16[/tex]