Odpowiedź:
P = 36√3 [j²]
Ob = 36 [j]
Szczegółowe wyjaśnienie:
[tex]h = \frac{a\sqrt}3}}{2}\\\\r = \frac{1}{3}h = \frac{a\sqrt{3}}{6}\\oraz\\r = 2\sqrt{3}\\\\\frac{a\sqrt{3}}{6} = 2\sqrt{3} \ \ \ |\cdot\frac{6}{\sqrt{3}}\\\\\underline{a = 12}[/tex]
[tex]P = \frac{a^{2}\sqrt{3}}{4} = \frac{12^{2}\cdot\sqrt{3}}{4}=\frac{144\sqrt{3}}{4} = \boxed{36\sqrt{3}}\\\\Ob = 3a = 3\cdot 12=\boxed{36}[/tex]
