Odpowiedź:
[tex]\frac{2}{3}\cdot(2\frac{5}{6}-1,2)=\frac{2}{3}\cdot(2\frac{5}{6}-1\frac{2}{10})=\frac{2}{3}\cdot(2\frac{5}{6}-1\frac{1}{5})=\frac{2}{3}\cdot(2\frac{25}{30}-1\frac{6}{30})=\frac{2}{3}\cdot1\frac{19}{30}=\\\\=\frac{\not2^1}{3}\cdot\frac{49}{\not30_{15}}=\frac{1}{3}\cdot\frac{49}{15}=\frac{49}{45}=1\frac{4}{45}[/tex]
