[tex]prosta:\\x - 2y-12=0\\-2y = -x + 12\\2y = x - 12\\y = \frac{1}{2} x - 6[/tex]
[tex]okrag:\\(x-3)^{2} + (y+2)^{2}=r^{2}\\(-1-3)^{2} + (-5+2)^{2} = r^{2}\\(-4)^{2} + (-3)^{2} = r^{2}\\16 + 9 = r^{2}\\r^{2} = 25\\r = 5\\\\(x-3)^{2} + (y+2)^{2} = 25[/tex]
[tex]wspolny:\\\left \{ {{y=\frac{1}{2}x- 6} \atop {(x-3)^{2} + (y+2)^{2}=25}} \right. \\\left \{ {{y=\frac{1}{2}x- 6} \atop {(x-3)^{2} + (\frac{1}{2}x- 6+2)^{2}=25}} \right. \\\left \{ {{y=\frac{1}{2}x- 6} \atop {(x-3)^{2} + (\frac{1}{2}x- 4)^{2}=25}} \right. \\\left \{ {{y=\frac{1}{2}x- 6} \atop {x^{2} - 6x + 9 + \frac{1}{4}x^{2} - 4x + 16 =25}} \right. \\\left \{ {{y=\frac{1}{2}x- 6} \atop {\frac{5}{4}x^{2} - 10x + 25=25}} \right. \\[/tex]
[tex]\left \{ {{y=\frac{1}{2}x- 6} \atop {\frac{5}{4}x^{2} - 10x = 0}} \right.\\\left \{ {{y=\frac{1}{2}x- 6} \atop {x(\frac{5}{4}x - 10) = 0}} \right.\\\\[/tex]
x₁ = 0 V 5x₂/4 - 10 = 0
x₁ = 0 v x₂ = 8
y₁ = -6 v y₂ = -2
punkty: A(0;-6) oraz B(8;-2)
