Odpowiedź :
Odpowiedź:
[tex]\left \{ {{2x+y=8} \atop {3x+4y=7}} \right. \\\left \{ {{y=8-2x} \atop {3x+4(8-2x)=7}} \right. \\\left \{ {{y=8-2x} \atop {3x+32-8x=7}} \right. \\\left \{ {{y=8-2x} \atop {3x-8x=7-32}} \right. \\\left \{ {{y=8-2x} \atop {-5x=-25/:(-5)}} \right. \\\left \{ {{y=8-2x} \atop {x=5}} \right. \\\left \{ {{y=8-2*5} \atop {x=5}} \right. \\\left \{ {{y=8-10} \atop {x=5}} \right. \\\left \{ {{y=-2} \atop {x=5}} \right. \\[/tex]
sprawdzam:
2·5+(-2)=10-2=8
3·5+4·(-2)=15-8=7
Rozwiąż układ równań metodą podstawiania :
3 x + 4 y = 7
2 x + y = 8
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3 x + 4 y = 7
y = 8 - 2 x
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3 x + 4 * (8 - 2 x) = 7
3 x + 32 - 8 x = 7
3 x - 8 x = 7 - 32
- 5 x = - 25 /: (- 5)
x = 5
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y = 8 - 2 x
y = 8 - 2 * 5
y = 8 - 10
y = - 2
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Sprawdzenie :
L₁: 3 * 5 + 4 * (- 2) = 15 - 8 = 7
P₁: 7
L₁ = P₁
L₂: 2 * 5 + (- 2) = 10 - 2 = 8
P₂: 8
L₂ = P₂