Odpowiedź:
[tex]\begin{cases}3x-y-7=0\\2x+5y=1\end{cases}\\\\\\\begin{cases}3x-y=7\\2x+5y=1\end{cases}\\\\\\\begin{cases}-y=7-3x\ \ /\cdot(-1)\\2x+5y=1\end{cases}\\\\\\\begin{cases}y=-7+3x\\2x+5y=1\end{cases}\\\\\\2x+5(-7+3x)=1\\\\2x-35+15x=1\\\\17x=1+35\\\\17x=36\ \ /:17\\\\x=\frac{36}{17}\\\\\\y=-7+3\cdot\frac{36}{17}=-7+\frac{108}{17}=-7+6\frac{6}{17}=-6\frac{17}{17}+6\frac{6}{17}=-\frac{11}{17}[/tex]
[tex]\begin{cases}x=\frac{36}{17}\\y=-\frac{11}{17}\end{cases}[/tex]
