Odpowiedź:
[tex]a)\ \ 3\sqrt{3}\cdot\sqrt{5}=3\sqrt{3\cdot5}=3\sqrt{15}\\\\b)\ \ \frac{\not12^4\sqrt{12}}{\not3_{1}\sqrt{3}}=\frac{4\sqrt{12}}{\sqrt{3}}=4\sqrt{\frac{12}{3}}=4\sqrt{4}=4\cdot2=8\\\\c)\ \ 4\sqrt[3]{5}\cdot\sqrt[3]{2}=4\sqrt[3]{5\cdot2}=4\sqrt[3]{10}\\\\d)\ \ \frac{\not16^4\sqrt[3]{-15}}{\not4_{1}\sqrt[3]{3}}=\frac{4\sqrt[3]{-15}}{\sqrt[3]{3}}=\frac{-4\sqrt[3]{15}}{\sqrt[3]{3}}=-4\sqrt[3]{\frac{15}{3}}=-4\sqrt[3]{5}[/tex]
