Odpowiedź:
e) P = 4 π cm² = π r² /: π
4 cm² = r²
r = 2 cm
L = 2π*r =2π* 2 cm = 4 π cm
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g) L = 12 cm = 2π*r / : 2π
r = [tex]\frac{6}{\pi }[/tex] cm
P = π r² = π *([tex]\frac{36}{\pi ^2}[/tex] ) cm² = [tex]\frac{36}{\pi }[/tex] cm²
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f ) L = 5 cm = 2π*r / : 2π
r = [tex]\frac{2,5}{\pi }[/tex] cm
P = π r² = π* [tex]\frac{6,25}{\pi ^2}[/tex] cm² = [tex]\frac{6,25}{\pi }[/tex] cm²
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h) P = 10 cm² = π*r²
r² = [tex]\frac{10}{\pi }[/tex] ⇒ r =[tex]\sqrt{\frac{10}{\pi } }[/tex] cm
L =2π * [tex]\sqrt{\frac{10}{\pi }[/tex] cm = 2 [tex]\sqrt{10 \pi }[/tex] cm
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Szczegółowe wyjaśnienie:
