[tex]Dane:\\d = 40 \ cm = 0,2 \ m\\n = 1200\\t = 1 \ min =60 \ s\\Szukane:\\\omega = ?\\\\Rozwiazanie\\\\\omega = \frac{2\pi }{T}\\\\ale\\\\T = \frac{t}{n} = \frac{60 \ s}{1200} = 0,05 \ s\\\\\omega = \frac{2\cdot3,14}{0,05 \ s}\\\\\boxed{\omega = 125,6\frac{rad}{s}}[/tex]
Odp. Prędkość kątowa wynosi 125,6 rad/s.