Odpowiedź :
Dane:
c= 12
sin α= 1/2
[tex] \sin( \alpha ) = \frac{a}{c} [/tex]
podstawiamy liczby
[tex] \frac{1}{2} = \frac{a}{12} [/tex]
[tex]a = \frac{12}{2} = 6[/tex]
i b można policzyć ze wzoru Pitagorasa
[tex] {a}^{2} + {b}^{2} = {c}^{2} \\ {6}^{2} + {b}^{2} = {12}^{2} \\ 36 + {b}^{2} = 144 \\ {b}^{2} = 144 - 36 \\ {b}^{2} = 108 \\ b = \sqrt{108} = \sqrt{36 \times 3} = 6 \sqrt{3} [/tex]