Odpowiedź :
[tex]Zad. 1\\\\A(2, -1)\\B(-4, 11)\\\\\left \{ {{-1=2a+b /*(*2)} \atop {11=-4a+b}} \right. \\+\left \{ {{-2=4a+2b} \atop {11=-4a+b}} \right. \\-2+11=2b+b\\9=3b /:3\\3=b\\\\-1=2a+3 /-3\\-4=2a /:2\\-2=a\\\\\\y=-2x+3[/tex]
[tex]Zad. 2\\f(x)=2x-14\\\\\text{Z osia OX}\\2x-14 = 0 /+14\\2x=14 /:2\\x=7\\\\\text{Z osia OY}\\y=2*0-14\\y=-14[/tex]
[tex]Zad. 3\\f(x)=3x-2\\\\a)\\\\3x-2=0 /+2\\3x=2 /:3\\x=\frac23\\\\b) \\\\f(\frac12)=3*\frac12-2\\f(\frac12)=\frac32-\frac42\\f(\frac12)=-\frac12\\\\c)\\\\\text{W zalaczniku}[/tex]
[tex]Zad. 4\\\\f(x)=-2x+5\\g(x)=x-4\\\\\\a)\\-2x+5=x-4\\-2x-x=-4-5\\-3x=-9 /:(-3)\\x=3\\\\y=3-4\\y=-1\\\\P(3, -1)[/tex]
[tex]b) \\\\-2x+5 < x-4 \\-2x-x < -4-5\\-3x < -9 /:(-3)\\x > 3\\\\x \in (3; \infty)[/tex]
[tex]c)\\\\\text{Uciete zdjecie, nie widac o jakie wartosci chodzi}[/tex]
[tex]Zad. 5\\\\\text{Nie widac wzoru funkcji}[/tex]