Cp1 = 69,2%
d = 1,41 g/cm^3 = 1410 g/dm^3
Mhno3 = 63 g/mol
Cm1 = (69,2% * 1410 g/dm^3)/(100% * 63 g/mol) = 97 572/6300 mol/dm^3 = 15,5 mol/dm^3
V1 = x
Cm2 = 2,5 mol/dm^3
V2 = y
(15,5x + 2,5y)/x+y = 10,5
15,5x + 2,5y = 10,5
x + y = 1
15,5(1-y) + 2,5y = 10,5
x = 1 - y
15,5 - 15,5y + 2,5y = 10,5
-13y = -5
y = 5/13 => x = 8/13
x/y = (8/13)/(5/13) = 8/13 * 13/5 = 8/5
odp: stosunek objetościowy musi byc równy 8/5, aby otrzymac 10,5 molowy roztwor.
