[tex]((-\frac12+3)-(0.4-\frac12))*(2-(1-\frac23))=\\(-\frac12+\frac62-\frac4{10}+\frac12)*(\frac63-\frac33+\frac23)=\\(\frac{30}{10}-\frac4{10})*\frac53=\\\frac{26}{10}*\frac53=\\\frac{26}{2}*\frac13=\\\frac{26}{6}=\frac{13}3=4\frac13[/tex]
