33.
[tex]a) \ \frac{9\sqrt{7}}{3\sqrt{7}} = \frac{9}{3} = \boxed{3}\\\\b) \ 4\sqrt{10}+3\sqrt{10} = \sqrt{10}\cdot(4+3) =\boxed{7\sqrt{10}}\\\\c) \ \frac{5+10\sqrt[3]{3}}{5} = \frac{5}{5} +\frac{10\sqrt[3]{3}}{5} = \boxed{1+2\sqrt[3]{3}}\\\\d) \ 4\sqrt[3]{5}+2\sqrt[3]{5}+3\sqrt[3]{-5}}=4\sqrt[3]{5}+2\sqrt[3]{5}-3\sqrt[3]{5} = \sqrt[3]{5}\cdot(4+2-3) = \boxed{3\sqrt[3]{5}}[/tex]
