Odpowiedź:
Obliczenia:
[tex]Dane:\\\Delta T = 300 \ K\\Q = 7,8 \ kJ = 7 \ 800 \ J\\c_{w} = 130\frac{J}{kg\cdot K}\\Szukane:\\m = ?\\\\Rozwiazanie\\\\Q = c_{w}\cdot m\cdot \Delra T \ \ \ |:(c_{w}\cdot \Delta T)\\\\m = \frac{Q}{c_{w}\cdot \Delta T}\\\\m = \frac{7800 \ J}{130\frac{J}{kg\cdpot K}\cdot300 \ K} = \frac{7800}{39000} \ kg\\\\\boxed{m = 0,2 \ kg}[/tex]