Odpowiedź:
(-1;4), (7;52)
Szczegółowe wyjaśnienie:
[tex]y=2x^2-6x-4\\\\(x,y)=(x,2x^2-6x-4)\\\\2x^2-6x-4-x^2=3\\\\x^2-6x-4-3=0\\\\x^2-6x-7=0\\\Delta=(-6)^2-4\cdot1\cdot(-7)=36+28=64\\\\\sqrt{\Delta}=\sqrt{64}=8\\\\x_1=\frac{6-8}{2\cdot1}=\frac{2}{2}=-1\\\\x_2=\frac{6+8}{2\cdot1}=\frac{14}{2}=7\\\\\\\\x=-1\ to \ y=2\cdot(-1)^2-6\cdot(-1)-4=2\cdot1+6-4=2+2=4\\\x=7\ to\ y=2\cdot7^2-6\cdot7-4=2\cdot49-42-4=98-46=52[/tex]
