Odpowiedź :
a)(√3+1)(2√3-2)=6-2√3+2√3-2=4
b)(x√2+1)(x-2√2)=x²√2-4x+x-2√2=x²√2-3x-2√2
c)(x+√2)(2√2+x) =2√2*x+x²+4+√2*x=3√2*x+x²+4
b)(x√2+1)(x-2√2)=x²√2-4x+x-2√2=x²√2-3x-2√2
c)(x+√2)(2√2+x) =2√2*x+x²+4+√2*x=3√2*x+x²+4
a)(√3+1)(2√3-2)=2*3-2√3+2√3-2=6-2√3+2√3-2=4
b)(x√2+1)(x-2√2)=x²√2-2x2+x-2√2=x²√2-4x+x-2√2=x²√2-3x-2√2
c)(x+√2)(2√2+x) =2x√2+ x²+ 2*2+ x√2= 2x√2+ x²+4+x√2= 3x√2+x²+4
b)(x√2+1)(x-2√2)=x²√2-2x2+x-2√2=x²√2-4x+x-2√2=x²√2-3x-2√2
c)(x+√2)(2√2+x) =2x√2+ x²+ 2*2+ x√2= 2x√2+ x²+4+x√2= 3x√2+x²+4