[tex]y=(3x-2)^2- \frac{1}{2}(6x-3)(3x+2)+12 \frac{1}{2}x -4[/tex]
[tex]y=9x^2-12x+4- \frac{1}{2}(18x^2+12x-9x-6)+12 \frac{1}{2}x -4[/tex]
[tex]y=9x^2-12x+4-9x^2-6x+4,5x+3+12 \frac{1}{2}x -4[/tex]
[tex]y=-x+3[/tex]
Obliczenia do tabelki:
[tex]x=0 \Rightarrow y=0+3=3[/tex]
[tex]x=3 \Rightarrow y=-3+3=0[/tex]
