Dane:
t1=2 [h]
t2=4,5 [h] t3=?
Roz:
s=v*t
s1=s2 v3- prędkosc prądu rzeki
(v1+v3)*t1=(v1-v3)*t2
v1t1+v3t1=v1t2-v3t2
v3t1+v3t2=v1t2-v1t1
v3*(t1+t2)=v1t2-v1t1 //(t1+t2)
v3=(v1t2-v1t1)/(t1+t2)
s=(v1+v3)*t1 ( !!!)
s=v3*t3
t3=s/v3
t3=(v1+v3)*t1/v3 (pod s podstawiam rownanie !!! :))
t3=(v1/v3+t1)
t3=[v1*(t1+t2)*t1/v1(t2-t1)]+t1]
t3=(t1+t2)*t1/(t2-t1)+t1
t3=(2+4,5)*t1/(4,5-2)+2
t3=6,5*2,5/2,5+2
t3= 8,5 [h]
Skad te zadanie? :)) Bardzo ciekawe :) pozdrawiam :)
