Rozwiązane

(4a-3)(3a+2)-a(a-1)=



Odpowiedź :

(4a-3)(3a+2)-a(a-1)=
=12a²+8a-9a-6-a²+a=
=11a²-6
(4a-3)(3a+2)-a(a-1)=12a²+8a-9a-6-a²+a = 11a²-6

11a²-6=0
11a²=6 /:11
a²=6/11
a=√6/11
Kinska
(4a-3)(3a+2)-a(a-1)= 12a²+8a-9a-6-a²+a=11a²-6