Odpowiedź :
C3H8-propan
masa węgla=12u
masa wodoru=1u
mC3H8=3*12+8*1=36+8=44
44-100%
36-x
x=36*100/44
x=81,8%
masa węgla=12u
masa wodoru=1u
mC3H8=3*12+8*1=36+8=44
44-100%
36-x
x=36*100/44
x=81,8%
propan -C₃H₈
mC₃H₈= 3 * 12u + 8 * 1u=44u
%C=36/44 * 100!=81,82%
%H=8/44 * 100%= 18,18%
mC₃H₈= 3 * 12u + 8 * 1u=44u
%C=36/44 * 100!=81,82%
%H=8/44 * 100%= 18,18%