Rozwiązane

Zmieszano 200g 20-procentowego ze 100g 10-procentowego roztworu wodorotlenku potasu.Oblicz stężenie procentowe powstałego roztworu.



Odpowiedź :

Dane:
mr₁ = 200 g
Cp₁ = 20 %
ms₁ = 40 g

mr₂ = 100 g
Cp₂ = 10%
ms₂ = 10 g

mrc = 200 g + 100 g = 300g
msc = 40 g + 10 g = 50g

Szukane:
Cp₃ = ?

Cp = ms*100%/mr
Cp = 50g*100%/300
Cp = 16,67 %

odp. Stężenie procentowe wynosi ok. 16,67%
dane:
mr1 = 200g
Cp1 = 20%
mr2 = 100g
Cp2 = 10%

szukane:
ms1 = ?
ms2 = ?
ms3 = ?
mr3 = ?
Cp3 = ?

Cp = ms / mr * 100%
ms = Cp * mr / 100%

ms1 = 20% * 200g / 100%
ms1 = 40g

ms2 = 10% * 100g / 100%
ms2 = 10g

ms3 = ms1 + ms2
ms3 = 40g + 10g
ms3 = 50g

mr3 = mr1 + mr2
mr3 = 200g + 100g
mr3 = 300g

Cp3 = ms3 / mr3 *100%
Cp3 = 50g / 300g * 100%
Cp3 = 16 2/3%

W przybliżeniu: 16,67%
ms - ?
Cp1 = 20%
mr1 = 200 g
Cp2 = 10%
mr2 = 100 g
Cp3 = ?

Wzór
ms1 = Cp1 x mr1 ÷ 100
ms = 20 % x 200g ÷100% = 40 g
ms = 40g

ms2 = Cp2 x mr2 ÷ 100
ms2 = 10 % x 100g ÷ 100 = 10g
ms2 = 10 g

Cp3 = (ms1+ms2) ÷ (mr1+mr2)*100%
Cp3 = (40g +10g) ÷ (200g + 100g)
Cp3 = 50g ÷ 300g
Cp3 = 16,7 i jest to wynik w zaokrągleniu można tez napisać 16, (6)