Odpowiedź :
a.
*ob= 16π
0b= 2πr = 16π
r= 8
pole = πr²
π8²= 64π
*ob= 2/3 πkm = 2 πr
r = 1/3 km
πr² = π(1/3)² = 1/9π km2
b.
*pole = 16πcm2 =πr²
r = 4 cm
ob =2πr = 2 ×π × 4 = 8π
* pole = 0,25 π mm2 = πr²
r= 0,5 mm
ob= 2 πr = 2 ×π× 0,5 = π
*ob= 16π
0b= 2πr = 16π
r= 8
pole = πr²
π8²= 64π
*ob= 2/3 πkm = 2 πr
r = 1/3 km
πr² = π(1/3)² = 1/9π km2
b.
*pole = 16πcm2 =πr²
r = 4 cm
ob =2πr = 2 ×π × 4 = 8π
* pole = 0,25 π mm2 = πr²
r= 0,5 mm
ob= 2 πr = 2 ×π× 0,5 = π