Rozwiązane

2⅓-3×(2-1\9)=
3-½×(2\5+3\7)=
te coś 1\9 2\5 i 3\7 to ulamki



Odpowiedź :

2⅓-3×(2-1\9)=2 1/3 - 6x+1/3= -6x + 2 2/3

3-½×(2\5+3\7)=3 - 1/5x- 3/14= -1/5x +(42/14 - 3/14)= -1/5x +39/14=
-1/5x+ 2 11/14
2⅓ - 3 × (2 - 1\9) = 2⅓ - 3 × (1 i 8/9) = 2⅓ - 5⅔ = -3⅓

3 - ½ × (2\5 + 3\7) = 3 - ½ × (14/35 + 15/35) = 3 - ½ × 29/35 = 3 - 145/350 = 2 i 205/350 = 2 i 41/70
Olka2170
2 1/3-3x(2-1/9=2 1/3-6x+1/3x=2 1/3-6 1/3x
3-1/2x(2/5+3/7)=3-1/2x(14/35+15/35)=3-29/70

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