Odpowiedź :
(C17H33COO)3C3H5 + 3H2---->(C17H35COO)3C3H5
1mol trioleinianu-------3mole wodoru
2mole trioleinianu---------xmoli wodoru
x = 6moli wodoru
(C₁₇H₃₃COO)₃C₃H₅+3H₂-->(C₁₇H₃₅COO)₃C₃H₅
1mol------------------3mol
2mol------------------xmol
x=2mol*3mol/1mol
x=6mol