[tex]\\\frac{2x+3}{x+2}=\frac{2x-1}{x+3}/*(x+2)(x+3), \ x\in R\backslash\{-3, -2\} \\. \\(x+3)(2x+3)=(x+2)(2x-1) \\2x^2+3x+6x+9=2x^2-x+4x-2 \\9x-3x=-2-9 \\6x=-11/:6 \\x=-\frac{11}{6} \\x=-1\frac56[/tex]
[tex]\frac{2x+3}{x+2}=\frac{2x-1}{x+3}\ D\in R/\{-3,-2\}<==mnozenie\ na\ krzyz\\\ \\\ (2x+3)(x+3)=(x+2)(2x-1)\\\ \\\ 2x^2+6x+3x+9=2x^2-x+4x-2\\\ \\\ 2x^2+9x+9=2x^2+3x-2/-2x^2\\\ \\\ 9x+9=3x-2/-3x\\\ \\\ 6x+9=-2/-9\\\ \\\ 6x=-11/:6\\\ \\\ x=\frac{-11}{6}\\\ \\\ x=-1\frac{5}{6}[/tex]