(4x² - 25)² - (2x - 5)²= [(2x -5)(2x+5)]² -(2x-5)² = (2x-5)² (2x+5)² - (2x-5)² = (2x-5)² [(2x+5)² - 1] = (2x-5)² (4x² +20x +24)
(2x-5)² (4x² +20x +24) = 0 <=>
(2x-5)² = 0 lub 4x² +20x +24 = 0
2x = 5 Δ = 400 - 384 = 16 √Δ = 4
x=2.5 lub x₁= -20 -4/8 = -24/8 = -3
x₂= -20 +4/8 = -16/8 = -2
x=2.5 lub x=-3 lub x = -2
(4x² - 25)² - (2x - 5)²= (x-2.5)(x+3)(x+2)
